Testcase: List

Implementing fmt::Display for a structure where the elements must each be handled sequentially is tricky. The problem is that each write! generates a fmt::Result. Proper handling of this requires dealing with all the results. Rust provides the ? operator for exactly this purpose.

Using ? on write! looks like this:

// Try `write!` to see if it errors. If it errors, return
// the error. Otherwise continue.
write!(f, "{}", value)?;

With ? available, implementing fmt::Display for a Vec is straightforward:

use std::fmt; // Import the `fmt` module.

// Define a structure named `List` containing a `Vec`.
struct List(Vec<i32>);

impl fmt::Display for List {
    fn fmt(&self, f: &mut fmt::Formatter) -> fmt::Result {
        // Extract the value using tuple indexing,
        // and create a reference to `vec`.
        let vec = &self.0;

        write!(f, "[")?;

        // Iterate over `v` in `vec` while enumerating the iteration
        // count in `count`.
        for (count, v) in vec.iter().enumerate() {
            // For every element except the first, add a comma.
            // Use the ? operator to return on errors.
            if count != 0 { write!(f, ", ")?; }
            write!(f, "{}", v)?;

        // Close the opened bracket and return a fmt::Result value.
        write!(f, "]")

fn main() {
    let v = List(vec![1, 2, 3]);
    println!("{}", v);


Try changing the program so that the index of each element in the vector is also printed. The new output should look like this:

[0: 1, 1: 2, 2: 3]

See also:

for, ref, Result, struct, ?, and vec!